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CBSE Class 10 Mathematics Question Paper 2011-2012 (SA-2)7
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Let C be the initial position of the plane above the ground and E the position of plane after 30 seconds. Let the speed of the plane be ν m/sec. Given ∠CAB = 60°, ∠EAD = 30°, BC = DE = 3600√3 m Distance covered by the plane in 30 sec = ν m/sec × 30 sec = 30 ν m (Distance = Speed × Time) ∴ CE = BD = 30ν m In ΔABC, ⇒ AB = 3600 m In ΔADE, ⇒ 3600 + 30 ν = 3600 × 3 ⇒ 30 ν = 10800 – 3600 = 7200 Speed of the plane = 240 m/sec = km/hr = 864 km/hr Thus, the speed of the plane is 864 km/hr.
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- CBSE Class 10 Mathematics Question Paper 2011-2012 (SA-2)
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