Polynomials related Questions by Balaji

  • 8August
  • 2014
  • 12
    6.1k
    A 4 digit prime no when divided by 24 leaves a remainder r. how many possible values can r take ?



    a)7



    b)8



    c)9



    d)10





    answer choice b



    solution



    24k+r=prime

    r is not equal to 0

    r can be 1

    if r=2 then 24k+r will multiple of 2

    24k+3=3(8k+1)

    r has to be coprime with 24

    r can be 1,5,7,11,13,17,19,23



    8 values totally nothing pi (24)


     


     



    Messages In This Thread
    Polynomials related question phase-2 - by Balaji - 08-08-2014, 11:15 PM
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