Polynomials related Questions by Balaji

[Balaji]

N has p factors



2N has 2p factors



3N has 4P/3 factors 



which of the follow could be N?



a) 36



b) 38



c) 40



d) 45

answer choice d



solution



no of factor of N = (a+1)(b+1)(c+1)


no of factor of 3N = (a+2)(b+1)(c+1)







(a+2)/(a+1)


=4/3





a=2











N is odd  no that multiple of 9