Probability related Questions by Balaji

  • 8August
  • 2014
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    BalajiSenior Member
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    08-08-2014, 11:33 PM Düzenlendi #2
    consider a 3 digits number abc. what is the probability that a>b>c ?



    a) 1/12



    b) 1/6



    c) 2/15



    d) 1/7





    answer choice d



    solution



    denominator = total no of 3 digit no = 9*10*10

    =900



    required probability = 84+36/900=120/900=2/15


     

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    probability related question phase - 2 - by Balaji - 08-08-2014, 11:33 PM